Power System
Power Factor Correction
Qc = P × (tanφ1 - tanφ2)
Variables
| Qc | Required Capacitor | kVAR |
| P | Load Power | kW |
Engineering Example
100 kW load improved from PF 0.75 to 0.95 requires about 55 kVAR.
Practical Site Example
Used to size capacitor banks.